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	<title>Comments on: 1, 1, 5, 17, 57, 189,</title>
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	<link>http://qingbo.org/archives/355.html</link>
	<description>醒也罢，梦也罢，人生苦短</description>
	<pubDate>Tue, 02 Dec 2008 09:06:22 +0000</pubDate>
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		<title>By: 星月轮转 &#187; Blog Archive &#187; 数列题的答案</title>
		<link>http://qingbo.org/archives/355.html/comment-page-1#comment-60902</link>
		<dc:creator>星月轮转 &#187; Blog Archive &#187; 数列题的答案</dc:creator>
		<pubDate>Mon, 03 Dec 2007 14:46:02 +0000</pubDate>
		<guid isPermaLink="false">http://www.qingbo.org/archives/355.html#comment-60902</guid>
		<description>[...] 前几天在blog上出了一道数字序列题，blacktulip很快给出了答案：  625? a(n)=a(n-1)*3+a(n-2)+1 (n&#62;2) [...]</description>
		<content:encoded><![CDATA[<p>[...] 前几天在blog上出了一道数字序列题，blacktulip很快给出了答案：  625? a(n)=a(n-1)*3+a(n-2)+1 (n&gt;2) [...]</p>
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	<item>
		<title>By: blacktulip</title>
		<link>http://qingbo.org/archives/355.html/comment-page-1#comment-59533</link>
		<dc:creator>blacktulip</dc:creator>
		<pubDate>Fri, 30 Nov 2007 13:28:03 +0000</pubDate>
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		<description>嘿嘿，小牛了一把</description>
		<content:encoded><![CDATA[<p>嘿嘿，小牛了一把</p>
]]></content:encoded>
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		<title>By: zhouqb</title>
		<link>http://qingbo.org/archives/355.html/comment-page-1#comment-59300</link>
		<dc:creator>zhouqb</dc:creator>
		<pubDate>Fri, 30 Nov 2007 02:30:06 +0000</pubDate>
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		<description>嗯，标准答案 :)
&lt;a href="http://www.research.att.com/~njas/sequences/A033538" rel="nofollow"&gt;http://www.research.att.com/~njas/sequences/A033538&lt;/a&gt;</description>
		<content:encoded><![CDATA[<p>嗯，标准答案 <img src='http://qingbo.org/wp-includes/images/smilies/icon_smile.gif' alt=':)' class='wp-smiley' /><br />
<a href="http://www.research.att.com/~njas/sequences/A033538" rel="nofollow">http://www.research.att.com/~njas/sequences/A033538</a></p>
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		<title>By: blacktulip</title>
		<link>http://qingbo.org/archives/355.html/comment-page-1#comment-59108</link>
		<dc:creator>blacktulip</dc:creator>
		<pubDate>Thu, 29 Nov 2007 17:27:36 +0000</pubDate>
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		<description>625? 
a(n)=a(n-1)*3+a(n-2)+1  (n&#62;2)</description>
		<content:encoded><![CDATA[<p>625?<br />
a(n)=a(n-1)*3+a(n-2)+1  (n&gt;2)</p>
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